What are the solutions to the equation 5x^2+40x=-75 ?

The solutions to the equation 5x^2+40x=-75 are x=-3,x=-5

Find the zeros of 5x^2+40x=-75

The zeros of 5x^2+40x=-75 are x=-3,x=-5

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5 x^{2} + 40 x = - 75

x = - 3, x = - 5

Solution steps

5 x^{2} + 40 x = - 75

Move

75

to the left side

5 x^{2} + 40 x + 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 5 \cdot 75}{2 \cdot 5}

4 0^{2} - 4 \cdot 5 \cdot 75 = 10

x_{1, 2} = \frac{- 40 \pm 10}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 40 + 10}{2 \cdot 5}, x_{2} = \frac{- 40 - 10}{2 \cdot 5}

x = \frac{- 40 + 10}{2 \cdot 5} : - 3

x = \frac{- 40 - 10}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

x = - 3, x = - 5

x^{2} - x + \frac{1}{8} = 0

x, 0 = x (1 - x) + m - h x

6 x^{2} - 5 x + 4 = 4 (3 x^{2} - 2 x + 1)

t, h = - 16 t^{2} + v^{0} t + h^{0}

7 x^{2} + 8 x - 3 = 0

What are the solutions to the equation 5x^2+40x=-75 ?
The solutions to the equation 5x^2+40x=-75 are x=-3,x=-5
Find the zeros of 5x^2+40x=-75
The zeros of 5x^2+40x=-75 are x=-3,x=-5