What are the solutions to the equation -x^2+7x=10 ?

The solutions to the equation -x^2+7x=10 are x=2,x=5

Find the zeros of -x^2+7x=10

The zeros of -x^2+7x=10 are x=2,x=5

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- x^{2} + 7 x = 10

x = 2, x = 5

Solution steps

- x^{2} + 7 x = 10

Move

10

to the left side

- x^{2} + 7 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) ( - 10 )}{2 ( - 1 )}

7^{2} - 4 (- 1) (- 10) = 3

x_{1, 2} = \frac{- 7 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 7 + 3}{2 ( - 1 )}, x_{2} = \frac{- 7 - 3}{2 ( - 1 )}

x = \frac{- 7 + 3}{2 ( - 1 )} : 2

x = \frac{- 7 - 3}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

x = 2, x = 5

14 = w (2 w - 3)

t^{2} + 2 t - 24 = 0

29.1 2^{2} = w^{2} + (3 w)^{2}

x^{2} - 88 = 12

x^{2} + 10 = 91

What are the solutions to the equation -x^2+7x=10 ?
The solutions to the equation -x^2+7x=10 are x=2,x=5
Find the zeros of -x^2+7x=10
The zeros of -x^2+7x=10 are x=2,x=5