What are the solutions to the equation 0.8x^2-24x+200=0 ?

The solutions to the equation 0.8x^2-24x+200=0 are x=15+5i,x=15-5i

Find the zeros of 0.8x^2-24x+200=0

The zeros of 0.8x^2-24x+200=0 are x=15+5i,x=15-5i

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0.8 x^{2} - 24 x + 200 = 0

x = 15 + 5 i, x = 15 - 5 i

Solution steps

0.8 x^{2} - 24 x + 200 = 0

Multiply both sides by

10

8 x^{2} - 240 x + 2000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 240 ) \pm ( - 240 ) ^{2} - 4 \cdot 8 \cdot 2000}{2 \cdot 8}

Simplify

(- 240)^{2} - 4 \cdot 8 \cdot 2000 : 80 i

x_{1, 2} = \frac{- ( - 240 ) \pm 80 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 240 ) + 80 i}{2 \cdot 8}, x_{2} = \frac{- ( - 240 ) - 80 i}{2 \cdot 8}

x = \frac{- ( - 240 ) + 80 i}{2 \cdot 8} : 15 + 5 i

x = \frac{- ( - 240 ) - 80 i}{2 \cdot 8} : 15 - 5 i

The solutions to the quadratic equation are:

x = 15 + 5 i, x = 15 - 5 i

x^{2} + 12 x + 144 = 0

10 x^{2} = 360

6 x^{2} - 11 x = 10

2 x^{2} + 5 x - 1

2 x^{2} + 5 x + 1

What are the solutions to the equation 0.8x^2-24x+200=0 ?
The solutions to the equation 0.8x^2-24x+200=0 are x=15+5i,x=15-5i
Find the zeros of 0.8x^2-24x+200=0
The zeros of 0.8x^2-24x+200=0 are x=15+5i,x=15-5i