What are the solutions to the equation 4x^2=225 ?

The solutions to the equation 4x^2=225 are x= 15/2 ,x=-15/2

Find the zeros of 4x^2=225

The zeros of 4x^2=225 are x= 15/2 ,x=-15/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} = 225

x = \frac{15}{2}, x = - \frac{15}{2}

Decimal Notation

x = 7.5, x = - 7.5

Solution steps

4 x^{2} = 225

Divide both sides by

4

x^{2} = \frac{225}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{225}{4}, x = - \frac{225}{4}

\frac{225}{4} = \frac{15}{2}

- \frac{225}{4} = - \frac{15}{2}

x = \frac{15}{2}, x = - \frac{15}{2}

x^{2} - 10 x + 30 = 9

x (x + 3) - 5 x = 3

0 = 3 x^{2} - 4 x - 2

4 x^{2} = 10 x

4 x^{2} = 13 x

What are the solutions to the equation 4x^2=225 ?
The solutions to the equation 4x^2=225 are x= 15/2 ,x=-15/2
Find the zeros of 4x^2=225
The zeros of 4x^2=225 are x= 15/2 ,x=-15/2