What are the solutions to the equation solvefor x,x^2+2xy+4=2xy ?

The solutions to the equation solvefor x,x^2+2xy+4=2xy are x=2i,x=-2i

Find the zeros of solvefor x,x^2+2xy+4=2xy

The zeros of solvefor x,x^2+2xy+4=2xy are x=2i,x=-2i

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solve for

x, x^{2} + 2 x y + 4 = 2 x y

x = 2 i, x = - 2 i

Solution steps

x^{2} + 2 x y + 4 = 2 x y

Move

4

to the right side

x^{2} + 2 x y = 2 x y - 4

Move

2 x y

to the left side

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

\frac{x ^{2} + 1}{2} = 2 x - 1

5 - x = 16 - 16 x + 4 x^{2}

- 4.9 x^{2} + 20 x + 75 = 0

6 x (x - 1) = 49 - 13 x

7 x^{2} + x + 3 = 0

What are the solutions to the equation solvefor x,x^2+2xy+4=2xy ?
The solutions to the equation solvefor x,x^2+2xy+4=2xy are x=2i,x=-2i
Find the zeros of solvefor x,x^2+2xy+4=2xy
The zeros of solvefor x,x^2+2xy+4=2xy are x=2i,x=-2i