What are the solutions to the equation 35x^2+2x-1=0 ?

The solutions to the equation 35x^2+2x-1=0 are x= 1/7 ,x=-1/5

Find the zeros of 35x^2+2x-1=0

The zeros of 35x^2+2x-1=0 are x= 1/7 ,x=-1/5

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35 x^{2} + 2 x - 1 = 0

x = \frac{1}{7}, x = - \frac{1}{5}

Decimal Notation

x = 0.14285 \dots, x = - 0.2

Solution steps

35 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 35 ( - 1 )}{2 \cdot 35}

2^{2} - 4 \cdot 35 (- 1) = 12

x_{1, 2} = \frac{- 2 \pm 12}{2 \cdot 35}

Separate the solutions

x_{1} = \frac{- 2 + 12}{2 \cdot 35}, x_{2} = \frac{- 2 - 12}{2 \cdot 35}

x = \frac{- 2 + 12}{2 \cdot 35} : \frac{1}{7}

x = \frac{- 2 - 12}{2 \cdot 35} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{1}{7}, x = - \frac{1}{5}

6 x^{2} + 7 x

5 0^{4}

m^{2} + 20 m + 19

\frac{( x + y ) ^{2} - z ^{2}}{x + y + z}

3 x^{2} = 10 x + 2

What are the solutions to the equation 35x^2+2x-1=0 ?
The solutions to the equation 35x^2+2x-1=0 are x= 1/7 ,x=-1/5
Find the zeros of 35x^2+2x-1=0
The zeros of 35x^2+2x-1=0 are x= 1/7 ,x=-1/5