What are the solutions to the equation 4x^2-72x=-68 ?

The solutions to the equation 4x^2-72x=-68 are x=17,x=1

Find the zeros of 4x^2-72x=-68

The zeros of 4x^2-72x=-68 are x=17,x=1

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4 x^{2} - 72 x = - 68

x = 17, x = 1

Solution steps

4 x^{2} - 72 x = - 68

Move

68

to the left side

4 x^{2} - 72 x + 68 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 72 ) \pm ( - 72 ) ^{2} - 4 \cdot 4 \cdot 68}{2 \cdot 4}

(- 72)^{2} - 4 \cdot 4 \cdot 68 = 64

x_{1, 2} = \frac{- ( - 72 ) \pm 64}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 72 ) + 64}{2 \cdot 4}, x_{2} = \frac{- ( - 72 ) - 64}{2 \cdot 4}

x = \frac{- ( - 72 ) + 64}{2 \cdot 4} : 17

x = \frac{- ( - 72 ) - 64}{2 \cdot 4} : 1

The solutions to the quadratic equation are:

x = 17, x = 1

- 5 x - x^{2} = 84

(6 - x) (2 - x) + 5 = 0

6 x^{2} + 6 x - 13 = 0

2 x (x - 6) = 3

x^{2} - 4 x - 1 = 0

What are the solutions to the equation 4x^2-72x=-68 ?
The solutions to the equation 4x^2-72x=-68 are x=17,x=1
Find the zeros of 4x^2-72x=-68
The zeros of 4x^2-72x=-68 are x=17,x=1