What are the solutions to the equation -x^2-4x+65=7 ?

The solutions to the equation -x^2-4x+65=7 are x=-2-sqrt(62),x=sqrt(62)-2

Find the zeros of -x^2-4x+65=7

The zeros of -x^2-4x+65=7 are x=-2-sqrt(62),x=sqrt(62)-2

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- x^{2} - 4 x + 65 = 7

x = - 2 - 62, x = 62 - 2

Decimal Notation

x = - 9.87400 \dots, x = 5.87400 \dots

Solution steps

- x^{2} - 4 x + 65 = 7

Move

7

to the left side

- x^{2} - 4 x + 58 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) \cdot 58}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) \cdot 58 = 262

x_{1, 2} = \frac{- ( - 4 ) \pm 2 62}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 62}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 2 62}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 2 62}{2 ( - 1 )} : - 2 - 62

x = \frac{- ( - 4 ) - 2 62}{2 ( - 1 )} : 62 - 2

The solutions to the quadratic equation are:

x = - 2 - 62, x = 62 - 2

m^{2} + 6 m = - 109

- 4 x - 12 = - x^{2}

6 x^{2} - 48 x - 1374 = 0

(x + 1)^{2} - 3 x = 7

5 x^{2} - 55 x + 25 = 0

What are the solutions to the equation -x^2-4x+65=7 ?
The solutions to the equation -x^2-4x+65=7 are x=-2-sqrt(62),x=sqrt(62)-2
Find the zeros of -x^2-4x+65=7
The zeros of -x^2-4x+65=7 are x=-2-sqrt(62),x=sqrt(62)-2