What are the solutions to the equation k^2+6k-16=0 ?

The solutions to the equation k^2+6k-16=0 are k=2,k=-8

Find the zeros of k^2+6k-16=0

The zeros of k^2+6k-16=0 are k=2,k=-8

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k^{2} + 6 k - 16 = 0

k = 2, k = - 8

Solution steps

k^{2} + 6 k - 16 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

k_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 6 + 10}{2 \cdot 1}, k_{2} = \frac{- 6 - 10}{2 \cdot 1}

k = \frac{- 6 + 10}{2 \cdot 1} : 2

k = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

k = 2, k = - 8

x^{2} + 11 x + 30 = 0

w^{2} = 8 (w - 6)

0 = 3 x^{2} - 6 x - 1

(s - 4)^{2} - 169 = 0

- 2 x^{2} + 6 x + 2 = 0

What are the solutions to the equation k^2+6k-16=0 ?
The solutions to the equation k^2+6k-16=0 are k=2,k=-8
Find the zeros of k^2+6k-16=0
The zeros of k^2+6k-16=0 are k=2,k=-8