What are the solutions to the equation (z+1)^2=-81 ?

The solutions to the equation (z+1)^2=-81 are z=9i-1,z=-9i-1

Find the zeros of (z+1)^2=-81

The zeros of (z+1)^2=-81 are z=9i-1,z=-9i-1

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(z + 1)^{2} = - 81

z = 9 i - 1, z = - 9 i - 1

Solution steps

(z + 1)^{2} = - 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 1 = - 81 : z = 9 i - 1

Solve

z + 1 = - - 81 : z = - 9 i - 1

The solutions to the quadratic equation are:

z = 9 i - 1, z = - 9 i - 1

p^{2} - 14 p + 10 = - 8 p

5 x^{2} - 2 = 3 - 3 x^{2}

a^{2} + 4 = 13 + 7

- x^{2} - 2 x + 10 = 0

2 x - 7 = - x^{2}

What are the solutions to the equation (z+1)^2=-81 ?
The solutions to the equation (z+1)^2=-81 are z=9i-1,z=-9i-1
Find the zeros of (z+1)^2=-81
The zeros of (z+1)^2=-81 are z=9i-1,z=-9i-1