What are the solutions to the equation 7y+2y^2=15 ?

The solutions to the equation 7y+2y^2=15 are y= 3/2 ,y=-5

Find the zeros of 7y+2y^2=15

The zeros of 7y+2y^2=15 are y= 3/2 ,y=-5

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7 y + 2 y^{2} = 15

y = \frac{3}{2}, y = - 5

Decimal Notation

y = 1.5, y = - 5

Solution steps

7 y + 2 y^{2} = 15

Move

15

to the left side

7 y + 2 y^{2} - 15 = 0

Write in the standard form

a x^{2} + b x + c = 0

2 y^{2} + 7 y - 15 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 15) = 13

y_{1, 2} = \frac{- 7 \pm 13}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- 7 + 13}{2 \cdot 2}, y_{2} = \frac{- 7 - 13}{2 \cdot 2}

y = \frac{- 7 + 13}{2 \cdot 2} : \frac{3}{2}

y = \frac{- 7 - 13}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

y = \frac{3}{2}, y = - 5

x^{2} + 2 x + 6 = 2 (x + 1)

(x) = 1500 + 5 x + 0.01 x^{2}

3 x^{2} + 18 x - 6

(x - 1)^{2} = (4 x - 7)^{2} + (3 x)^{2}

2 (x + 3)^{2} = 90

What are the solutions to the equation 7y+2y^2=15 ?
The solutions to the equation 7y+2y^2=15 are y= 3/2 ,y=-5
Find the zeros of 7y+2y^2=15
The zeros of 7y+2y^2=15 are y= 3/2 ,y=-5