What are the solutions to the equation t+t^2=0 ?

The solutions to the equation t+t^2=0 are t=0,t=-1

Find the zeros of t+t^2=0

The zeros of t+t^2=0 are t=0,t=-1

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t + t^{2} = 0

t = 0, t = - 1

Solution steps

t + t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

t^{2} + t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot 0 = 1

t_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 1 + 1}{2 \cdot 1}, t_{2} = \frac{- 1 - 1}{2 \cdot 1}

t = \frac{- 1 + 1}{2 \cdot 1} : 0

t = \frac{- 1 - 1}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

t = 0, t = - 1

\frac{x ^{2}}{3} = 3 x

4 x (x + 7) + 48 = 0

- 12 w = 4 w^{2} + 9

(f - 2)^{2} = - 4 f^{2}

x (x - 1) - 2 x + 2 = 0

What are the solutions to the equation t+t^2=0 ?
The solutions to the equation t+t^2=0 are t=0,t=-1
Find the zeros of t+t^2=0
The zeros of t+t^2=0 are t=0,t=-1