What are the solutions to the equation -6+3x^2=-39 ?

The solutions to the equation -6+3x^2=-39 are x=sqrt(11)i,x=-sqrt(11)i

Find the zeros of -6+3x^2=-39

The zeros of -6+3x^2=-39 are x=sqrt(11)i,x=-sqrt(11)i

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- 6 + 3 x^{2} = - 39

x = 11 i, x = - 11 i

Solution steps

- 6 + 3 x^{2} = - 39

Move

6

to the right side

3 x^{2} = - 33

Divide both sides by

3

x^{2} = - 11

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 11, x = - - 11

- 11 = 11 i

- - 11 = - 11 i

x = 11 i, x = - 11 i

2 x^{2} - x - 28 = 0

100 x^{2} = 0

8 x^{2} - 43 x - 30 = 0

\frac{1}{2} (c - 8)^{2} = 8

30 x - 0.24 x^{2} = 275 + 12 x

What are the solutions to the equation -6+3x^2=-39 ?
The solutions to the equation -6+3x^2=-39 are x=sqrt(11)i,x=-sqrt(11)i
Find the zeros of -6+3x^2=-39
The zeros of -6+3x^2=-39 are x=sqrt(11)i,x=-sqrt(11)i