What are the solutions to the equation 9y+5y^2=18 ?

The solutions to the equation 9y+5y^2=18 are y= 6/5 ,y=-3

Find the zeros of 9y+5y^2=18

The zeros of 9y+5y^2=18 are y= 6/5 ,y=-3

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9 y + 5 y^{2} = 18

y = \frac{6}{5}, y = - 3

Decimal Notation

y = 1.2, y = - 3

Solution steps

9 y + 5 y^{2} = 18

Move

18

to the left side

9 y + 5 y^{2} - 18 = 0

Write in the standard form

a x^{2} + b x + c = 0

5 y^{2} + 9 y - 18 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 ( - 18 )}{2 \cdot 5}

9^{2} - 4 \cdot 5 (- 18) = 21

y_{1, 2} = \frac{- 9 \pm 21}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 9 + 21}{2 \cdot 5}, y_{2} = \frac{- 9 - 21}{2 \cdot 5}

y = \frac{- 9 + 21}{2 \cdot 5} : \frac{6}{5}

y = \frac{- 9 - 21}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

y = \frac{6}{5}, y = - 3

7 x^{2} + 2 x = x + 5 x^{2}

5 x^{2} + 1 = 9

5 x^{2} + 1 = 1

- 9 - x + x^{2} = - 5 x

- 6 x^{2} - 4 x - 1 = 0

What are the solutions to the equation 9y+5y^2=18 ?
The solutions to the equation 9y+5y^2=18 are y= 6/5 ,y=-3
Find the zeros of 9y+5y^2=18
The zeros of 9y+5y^2=18 are y= 6/5 ,y=-3