What are the solutions to the equation 11^2+7^2=x^2 ?

The solutions to the equation 11^2+7^2=x^2 are x=sqrt(170),x=-sqrt(170)

Find the zeros of 11^2+7^2=x^2

The zeros of 11^2+7^2=x^2 are x=sqrt(170),x=-sqrt(170)

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1 1^{2} + 7^{2} = x^{2}

x = 170, x = - 170

Decimal Notation

x = 13.03840 \dots, x = - 13.03840 \dots

Solution steps

1 1^{2} + 7^{2} = x^{2}

Switch sides

x^{2} = 1 1^{2} + 7^{2}

Simplify

1 1^{2} + 7^{2} : 170

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 170, x = - 170

x^{2} + 2 x - 72 = 0

- 6 x^{2} + 16 x + 2 = 0

(17 - y)^{2} + y^{2} = 169

x^{2} + 19 x + 78 = 0

\frac{4}{3} x^{2} = 48

What are the solutions to the equation 11^2+7^2=x^2 ?
The solutions to the equation 11^2+7^2=x^2 are x=sqrt(170),x=-sqrt(170)
Find the zeros of 11^2+7^2=x^2
The zeros of 11^2+7^2=x^2 are x=sqrt(170),x=-sqrt(170)