What are the solutions to the equation -6=y^2-5y ?

The solutions to the equation -6=y^2-5y are y=3,y=2

Find the zeros of -6=y^2-5y

The zeros of -6=y^2-5y are y=3,y=2

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- 6 = y^{2} - 5 y

y = 3, y = 2

Solution steps

- 6 = y^{2} - 5 y

Switch sides

y^{2} - 5 y = - 6

Move

6

to the left side

y^{2} - 5 y + 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

y_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, y_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

y = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

y = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

y = 3, y = 2

625

c^{2} - 2 = 0

42 = \frac{36 + p}{1.7}

(5)^{- 2}

9 m^{2} + 9 m + 56 = 8 m^{2} - 6 m

What are the solutions to the equation -6=y^2-5y ?
The solutions to the equation -6=y^2-5y are y=3,y=2
Find the zeros of -6=y^2-5y
The zeros of -6=y^2-5y are y=3,y=2