What are the solutions to the equation 16x^2+25=-40x ?

The solutions to the equation 16x^2+25=-40x are x=-5/4

Find the zeros of 16x^2+25=-40x

The zeros of 16x^2+25=-40x are x=-5/4

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16 x^{2} + 25 = - 40 x

x = - \frac{5}{4}

Decimal Notation

x = - 1.25

Solution steps

16 x^{2} + 25 = - 40 x

Move

40 x

to the left side

16 x^{2} + 25 + 40 x = 0

Write in the standard form

a x^{2} + b x + c = 0

16 x^{2} + 40 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 16 \cdot 25}{2 \cdot 16}

4 0^{2} - 4 \cdot 16 \cdot 25 = 0

x_{1, 2} = \frac{- 40 \pm 0}{2 \cdot 16}

x = \frac{- 40}{2 \cdot 16}

\frac{- 40}{2 \cdot 16} = - \frac{5}{4}

x = - \frac{5}{4}

The solution to the quadratic equation is:

x = - \frac{5}{4}

x^{2} - 11 x - 2 = 0

r^{2} - 49 = 0

4 x^{2} + 236 = 64 x

x^{2} + 14 = 30

x^{2} - 6 x + 15 = 3 (x - 1)

What are the solutions to the equation 16x^2+25=-40x ?
The solutions to the equation 16x^2+25=-40x are x=-5/4
Find the zeros of 16x^2+25=-40x
The zeros of 16x^2+25=-40x are x=-5/4