What are the solutions to the equation x^2-9x+4=24 ?

The solutions to the equation x^2-9x+4=24 are x=(9+sqrt(161))/2 ,x=(9-sqrt(161))/2

Find the zeros of x^2-9x+4=24

The zeros of x^2-9x+4=24 are x=(9+sqrt(161))/2 ,x=(9-sqrt(161))/2

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x^{2} - 9 x + 4 = 24

x = \frac{9 + 161}{2}, x = \frac{9 - 161}{2}

Decimal Notation

x = 10.84428 \dots, x = - 1.84428 \dots

Solution steps

x^{2} - 9 x + 4 = 24

Move

24

to the left side

x^{2} - 9 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 20) = 161

x_{1, 2} = \frac{- ( - 9 ) \pm 161}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 161}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 161}{2 \cdot 1}

x = \frac{- ( - 9 ) + 161}{2 \cdot 1} : \frac{9 + 161}{2}

x = \frac{- ( - 9 ) - 161}{2 \cdot 1} : \frac{9 - 161}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 161}{2}, x = \frac{9 - 161}{2}

\frac{6 ^{3}}{7 ^{2}} = x^{2}

- 4 - 5 v^{2} = - 364

3 x^{2} + 2 x = 11

6 x^{2} + 3 x - 630 = 0

x^{2} = 10 x - 61

What are the solutions to the equation x^2-9x+4=24 ?
The solutions to the equation x^2-9x+4=24 are x=(9+sqrt(161))/2 ,x=(9-sqrt(161))/2
Find the zeros of x^2-9x+4=24
The zeros of x^2-9x+4=24 are x=(9+sqrt(161))/2 ,x=(9-sqrt(161))/2