What are the solutions to the equation completesquare x^2-14x-4=0 ?

The solutions to the equation completesquare x^2-14x-4=0 are x=sqrt(53)+7,x=-sqrt(53)+7

Find the zeros of completesquare x^2-14x-4=0

The zeros of completesquare x^2-14x-4=0 are x=sqrt(53)+7,x=-sqrt(53)+7

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x^{2} - 14 x - 4 = 0

x = 53 + 7, x = - 53 + 7

Decimal Notation

x = 14.28010 \dots, x = - 0.28010 \dots

Solution steps

x^{2} - 14 x - 4 = 0

Move

4

to the right side

x^{2} - 14 x = 4

Rewrite in the form

(x + a)^{2} = b

(x - 7)^{2} = 53

For

the solutions are

f (x) = a, - a

Solve

x - 7 = 53 : x = 53 + 7

Solve

x - 7 = - 53 : x = - 53 + 7

The solutions to the quadratic equation are:

x = 53 + 7, x = - 53 + 7

54 = 0.04 x^{2} + 0.2 x + 12

x^{2} - 6 x - 2

x^{2} - 6 x - 6

t^{2} - 4 t - 2 = 0

5 x^{2} = 18 x + 8

What are the solutions to the equation completesquare x^2-14x-4=0 ?
The solutions to the equation completesquare x^2-14x-4=0 are x=sqrt(53)+7,x=-sqrt(53)+7
Find the zeros of completesquare x^2-14x-4=0
The zeros of completesquare x^2-14x-4=0 are x=sqrt(53)+7,x=-sqrt(53)+7