What are the solutions to the equation -2x^2+4x+11=0 ?

The solutions to the equation -2x^2+4x+11=0 are x=-(-2+sqrt(26))/2 ,x=(2+sqrt(26))/2

Find the zeros of -2x^2+4x+11=0

The zeros of -2x^2+4x+11=0 are x=-(-2+sqrt(26))/2 ,x=(2+sqrt(26))/2

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- 2 x^{2} + 4 x + 11 = 0

x = - \frac{- 2 + 26}{2}, x = \frac{2 + 26}{2}

Decimal Notation

x = - 1.54950 \dots, x = 3.54950 \dots

Solution steps

- 2 x^{2} + 4 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) \cdot 11}{2 ( - 2 )}

4^{2} - 4 (- 2) \cdot 11 = 226

x_{1, 2} = \frac{- 4 \pm 2 26}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 26}{2 ( - 2 )}, x_{2} = \frac{- 4 - 2 26}{2 ( - 2 )}

x = \frac{- 4 + 2 26}{2 ( - 2 )} : - \frac{- 2 + 26}{2}

x = \frac{- 4 - 2 26}{2 ( - 2 )} : \frac{2 + 26}{2}

The solutions to the quadratic equation are:

x = - \frac{- 2 + 26}{2}, x = \frac{2 + 26}{2}

p^{2} + 14 p - 38

x^{2} - 10 x - 11 = - 28

9 x^{2} - 7 x - 16 = 0

4.8 x - 0.36 x^{2} = 0

9 x^{2} - 60 x + 60 = 0

What are the solutions to the equation -2x^2+4x+11=0 ?
The solutions to the equation -2x^2+4x+11=0 are x=-(-2+sqrt(26))/2 ,x=(2+sqrt(26))/2
Find the zeros of -2x^2+4x+11=0
The zeros of -2x^2+4x+11=0 are x=-(-2+sqrt(26))/2 ,x=(2+sqrt(26))/2