What are the solutions to the equation -7x^2-x+8=0 ?

The solutions to the equation -7x^2-x+8=0 are x=-8/7 ,x=1

Find the zeros of -7x^2-x+8=0

The zeros of -7x^2-x+8=0 are x=-8/7 ,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 7 x^{2} - x + 8 = 0

x = - \frac{8}{7}, x = 1

Decimal Notation

x = - 1.14285 \dots, x = 1

Solution steps

- 7 x^{2} - x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 7 ) \cdot 8}{2 ( - 7 )}

(- 1)^{2} - 4 (- 7) \cdot 8 = 15

x_{1, 2} = \frac{- ( - 1 ) \pm 15}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 15}{2 ( - 7 )}, x_{2} = \frac{- ( - 1 ) - 15}{2 ( - 7 )}

x = \frac{- ( - 1 ) + 15}{2 ( - 7 )} : - \frac{8}{7}

x = \frac{- ( - 1 ) - 15}{2 ( - 7 )} : 1

The solutions to the quadratic equation are:

x = - \frac{8}{7}, x = 1

2 z^{2} - 16 z - 1768 = 0

x^{2} - 10 x + 81 = 0

c^{2} = 1

x^{2} + 2 x = 10 x

- x^{2} + 2 x + 0 = 0

What are the solutions to the equation -7x^2-x+8=0 ?
The solutions to the equation -7x^2-x+8=0 are x=-8/7 ,x=1
Find the zeros of -7x^2-x+8=0
The zeros of -7x^2-x+8=0 are x=-8/7 ,x=1