What are the solutions to the equation 4x^2+9x-11=2x^2+10x ?

The solutions to the equation 4x^2+9x-11=2x^2+10x are x=(1+sqrt(89))/4 ,x=(1-sqrt(89))/4

Find the zeros of 4x^2+9x-11=2x^2+10x

The zeros of 4x^2+9x-11=2x^2+10x are x=(1+sqrt(89))/4 ,x=(1-sqrt(89))/4

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4 x^{2} + 9 x - 11 = 2 x^{2} + 10 x

x = \frac{1 + 89}{4}, x = \frac{1 - 89}{4}

Decimal Notation

x = 2.60849 \dots, x = - 2.10849 \dots

Solution steps

4 x^{2} + 9 x - 11 = 2 x^{2} + 10 x

Move

10 x

to the left side

4 x^{2} - x - 11 = 2 x^{2}

Move

2 x^{2}

to the left side

2 x^{2} - x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 11 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 11) = 89

x_{1, 2} = \frac{- ( - 1 ) \pm 89}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 89}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 89}{2 \cdot 2}

x = \frac{- ( - 1 ) + 89}{2 \cdot 2} : \frac{1 + 89}{4}

x = \frac{- ( - 1 ) - 89}{2 \cdot 2} : \frac{1 - 89}{4}

The solutions to the quadratic equation are:

x = \frac{1 + 89}{4}, x = \frac{1 - 89}{4}

x^{2} + (2 x)^{2} = 80

- 4.9 x^{2} + 5 x + 40 = 0

x^{2} + 2 x = - 26

a^{2} = 2 a - 1

15 = x^{2} + 2 x

What are the solutions to the equation 4x^2+9x-11=2x^2+10x ?
The solutions to the equation 4x^2+9x-11=2x^2+10x are x=(1+sqrt(89))/4 ,x=(1-sqrt(89))/4
Find the zeros of 4x^2+9x-11=2x^2+10x
The zeros of 4x^2+9x-11=2x^2+10x are x=(1+sqrt(89))/4 ,x=(1-sqrt(89))/4