What are the solutions to the equation -x^2+18x-22=-2 ?

The solutions to the equation -x^2+18x-22=-2 are x=9-sqrt(61),x=9+sqrt(61)

Find the zeros of -x^2+18x-22=-2

The zeros of -x^2+18x-22=-2 are x=9-sqrt(61),x=9+sqrt(61)

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- x^{2} + 18 x - 22 = - 2

x = 9 - 61, x = 9 + 61

Decimal Notation

x = 1.18975 \dots, x = 16.81024 \dots

Solution steps

- x^{2} + 18 x - 22 = - 2

Move

2

to the left side

- x^{2} + 18 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 1 ) ( - 20 )}{2 ( - 1 )}

1 8^{2} - 4 (- 1) (- 20) = 261

x_{1, 2} = \frac{- 18 \pm 2 61}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 18 + 2 61}{2 ( - 1 )}, x_{2} = \frac{- 18 - 2 61}{2 ( - 1 )}

x = \frac{- 18 + 2 61}{2 ( - 1 )} : 9 - 61

x = \frac{- 18 - 2 61}{2 ( - 1 )} : 9 + 61

The solutions to the quadratic equation are:

x = 9 - 61, x = 9 + 61

y^{2} + y = 6

9 x^{2} + 18 x + 10 = 0

x^{2} - 2.457 x + 1.25 = 0

12 \cdot x^{2} = 48

x, 3 x^{2} 2 y - 6 = x^{2} - x^{2}

What are the solutions to the equation -x^2+18x-22=-2 ?
The solutions to the equation -x^2+18x-22=-2 are x=9-sqrt(61),x=9+sqrt(61)
Find the zeros of -x^2+18x-22=-2
The zeros of -x^2+18x-22=-2 are x=9-sqrt(61),x=9+sqrt(61)