What are the solutions to the equation x^2+5x-2x=0 ?

The solutions to the equation x^2+5x-2x=0 are x=0,x=-3

Find the zeros of x^2+5x-2x=0

The zeros of x^2+5x-2x=0 are x=0,x=-3

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x^{2} + 5 x - 2 x = 0

x = 0, x = - 3

Solution steps

x^{2} + 5 x - 2 x = 0

Refine

x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 \cdot 1}, x_{2} = \frac{- 3 - 3}{2 \cdot 1}

x = \frac{- 3 + 3}{2 \cdot 1} : 0

x = \frac{- 3 - 3}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 0, x = - 3

x^{2} - 10 x - 25 = 15 - 13 x

x^{2} - 24 x + 70 = - 8 x + 27

x^{2} - 12 x + 4 = 0

x \cdot (x + 1) = 30

7 x^{2} - 20 = 6 x

What are the solutions to the equation x^2+5x-2x=0 ?
The solutions to the equation x^2+5x-2x=0 are x=0,x=-3
Find the zeros of x^2+5x-2x=0
The zeros of x^2+5x-2x=0 are x=0,x=-3