What are the solutions to the equation 5y(y-2)=2 ?

The solutions to the equation 5y(y-2)=2 are y=(5+sqrt(35))/5 ,y=(5-sqrt(35))/5

Find the zeros of 5y(y-2)=2

The zeros of 5y(y-2)=2 are y=(5+sqrt(35))/5 ,y=(5-sqrt(35))/5

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5 y (y - 2) = 2

y = \frac{5 + 35}{5}, y = \frac{5 - 35}{5}

Decimal Notation

y = 2.18321 \dots, y = - 0.18321 \dots

Solution steps

5 y (y - 2) = 2

Expand

5 y (y - 2) : 5 y^{2} - 10 y

5 y^{2} - 10 y = 2

Move

2

to the left side

5 y^{2} - 10 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 10)^{2} - 4 \cdot 5 (- 2) = 235

y_{1, 2} = \frac{- ( - 10 ) \pm 2 35}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 2 35}{2 \cdot 5}, y_{2} = \frac{- ( - 10 ) - 2 35}{2 \cdot 5}

y = \frac{- ( - 10 ) + 2 35}{2 \cdot 5} : \frac{5 + 35}{5}

y = \frac{- ( - 10 ) - 2 35}{2 \cdot 5} : \frac{5 - 35}{5}

The solutions to the quadratic equation are:

y = \frac{5 + 35}{5}, y = \frac{5 - 35}{5}

3 x (x - 3) = 11 x^{2} - 10 x

12 = - 2.7 t^{2} + 30 t + 6.5

35 x^{2} - 6 = x

a^{2} - 6 a = 0

18 x^{2} + 19 x + (- 7) = 0

What are the solutions to the equation 5y(y-2)=2 ?
The solutions to the equation 5y(y-2)=2 are y=(5+sqrt(35))/5 ,y=(5-sqrt(35))/5
Find the zeros of 5y(y-2)=2
The zeros of 5y(y-2)=2 are y=(5+sqrt(35))/5 ,y=(5-sqrt(35))/5