What are the solutions to the equation solvefor x,(x-C^1)^2+y^2=C^2 ?

The solutions to the equation solvefor x,(x-C^1)^2+y^2=C^2 are x=sqrt(C^2-y^2)+C,x=-sqrt(C^2-y^2)+C

Find the zeros of solvefor x,(x-C^1)^2+y^2=C^2

The zeros of solvefor x,(x-C^1)^2+y^2=C^2 are x=sqrt(C^2-y^2)+C,x=-sqrt(C^2-y^2)+C

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solve for

x, (x - C^{1})^{2} + y^{2} = C^{2}

x = C^{2} - y^{2} + C, x = - C^{2} - y^{2} + C

Solution steps

(x - C^{1})^{2} + y^{2} = C^{2}

Move

y^{2}

to the right side

(x - C^{1})^{2} = C^{2} - y^{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - C^{1} = C^{2} - y^{2} : x = C^{2} - y^{2} + C

Solve

x - C^{1} = - C^{2} - y^{2} : x = - C^{2} - y^{2} + C

The solutions to the quadratic equation are:

x = C^{2} - y^{2} + C, x = - C^{2} - y^{2} + C

x^{2} + 3 x^{2} - 4 x - 12 = 0

- 2 = x^{2} + 2 x

v, F = \frac{z M v ^{2}}{r}

k^{2} - 14 k - 28 = 0

5 y + 3 y^{2} = 28

What are the solutions to the equation solvefor x,(x-C^1)^2+y^2=C^2 ?
The solutions to the equation solvefor x,(x-C^1)^2+y^2=C^2 are x=sqrt(C^2-y^2)+C,x=-sqrt(C^2-y^2)+C
Find the zeros of solvefor x,(x-C^1)^2+y^2=C^2
The zeros of solvefor x,(x-C^1)^2+y^2=C^2 are x=sqrt(C^2-y^2)+C,x=-sqrt(C^2-y^2)+C