What are the solutions to the equation 2x^2-9=12x ?

The solutions to the equation 2x^2-9=12x are x=(3(2+sqrt(6)))/2 ,x=(3(2-sqrt(6)))/2

Find the zeros of 2x^2-9=12x

The zeros of 2x^2-9=12x are x=(3(2+sqrt(6)))/2 ,x=(3(2-sqrt(6)))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 9 = 12 x

x = \frac{3 ( 2 + 6 )}{2}, x = \frac{3 ( 2 - 6 )}{2}

Decimal Notation

x = 6.67423 \dots, x = - 0.67423 \dots

Solution steps

2 x^{2} - 9 = 12 x

Move

12 x

to the left side

2 x^{2} - 9 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 (- 9) = 66

x_{1, 2} = \frac{- ( - 12 ) \pm 6 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 6}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 6 6}{2 \cdot 2}

x = \frac{- ( - 12 ) + 6 6}{2 \cdot 2} : \frac{3 ( 2 + 6 )}{2}

x = \frac{- ( - 12 ) - 6 6}{2 \cdot 2} : \frac{3 ( 2 - 6 )}{2}

The solutions to the quadratic equation are:

x = \frac{3 ( 2 + 6 )}{2}, x = \frac{3 ( 2 - 6 )}{2}

v^{2} - 3 = - 16

X^{2} - 6 X + 2 = 0

e^{2} = 90

9 x^{2} - 2260 x + 129600 = 0

2 x (x + 1) = 5

What are the solutions to the equation 2x^2-9=12x ?
The solutions to the equation 2x^2-9=12x are x=(3(2+sqrt(6)))/2 ,x=(3(2-sqrt(6)))/2
Find the zeros of 2x^2-9=12x
The zeros of 2x^2-9=12x are x=(3(2+sqrt(6)))/2 ,x=(3(2-sqrt(6)))/2