What are the solutions to the equation 3x^2+19x-40=0 ?

The solutions to the equation 3x^2+19x-40=0 are x= 5/3 ,x=-8

Find the zeros of 3x^2+19x-40=0

The zeros of 3x^2+19x-40=0 are x= 5/3 ,x=-8

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3 x^{2} + 19 x - 40 = 0

x = \frac{5}{3}, x = - 8

Decimal Notation

x = 1.66666 \dots, x = - 8

Solution steps

3 x^{2} + 19 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 3 ( - 40 )}{2 \cdot 3}

1 9^{2} - 4 \cdot 3 (- 40) = 29

x_{1, 2} = \frac{- 19 \pm 29}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 19 + 29}{2 \cdot 3}, x_{2} = \frac{- 19 - 29}{2 \cdot 3}

x = \frac{- 19 + 29}{2 \cdot 3} : \frac{5}{3}

x = \frac{- 19 - 29}{2 \cdot 3} : - 8

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - 8

x^{2} + 5 x + 3 = 0

8 x^{2} + 8 x - 6 = 0

4 x^{2} - 4 x + 17 = 0

y^{2} - 8 y + 10 = 0

\frac{1}{8} = x^{2}

What are the solutions to the equation 3x^2+19x-40=0 ?
The solutions to the equation 3x^2+19x-40=0 are x= 5/3 ,x=-8
Find the zeros of 3x^2+19x-40=0
The zeros of 3x^2+19x-40=0 are x= 5/3 ,x=-8