What are the solutions to the equation -200x^2+200x-40=0 ?

The solutions to the equation -200x^2+200x-40=0 are x=(5-sqrt(5))/(10),x=(5+sqrt(5))/(10)

Find the zeros of -200x^2+200x-40=0

The zeros of -200x^2+200x-40=0 are x=(5-sqrt(5))/(10),x=(5+sqrt(5))/(10)

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- 200 x^{2} + 200 x - 40 = 0

x = \frac{5 - 5}{10}, x = \frac{5 + 5}{10}

Decimal Notation

x = 0.27639 \dots, x = 0.72360 \dots

Solution steps

- 200 x^{2} + 200 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 200 \pm 20 0 ^{2} - 4 ( - 200 ) ( - 40 )}{2 ( - 200 )}

20 0^{2} - 4 (- 200) (- 40) = 405

x_{1, 2} = \frac{- 200 \pm 40 5}{2 ( - 200 )}

Separate the solutions

x_{1} = \frac{- 200 + 40 5}{2 ( - 200 )}, x_{2} = \frac{- 200 - 40 5}{2 ( - 200 )}

x = \frac{- 200 + 40 5}{2 ( - 200 )} : \frac{5 - 5}{10}

x = \frac{- 200 - 40 5}{2 ( - 200 )} : \frac{5 + 5}{10}

The solutions to the quadratic equation are:

x = \frac{5 - 5}{10}, x = \frac{5 + 5}{10}

x^{2} = 6^{2} + 5^{2}

10 x^{2} - 24 x - 19 = - 9 x^{2} - 24 x

4 a^{2} - 100 = 0

2 x^{2} + 5 x - 33 = 0

x^{2} - (m + 4) x + 5 m - 8 = 0

What are the solutions to the equation -200x^2+200x-40=0 ?
The solutions to the equation -200x^2+200x-40=0 are x=(5-sqrt(5))/(10),x=(5+sqrt(5))/(10)
Find the zeros of -200x^2+200x-40=0
The zeros of -200x^2+200x-40=0 are x=(5-sqrt(5))/(10),x=(5+sqrt(5))/(10)