What are the solutions to the equation m^2-4m+4=8 ?

The solutions to the equation m^2-4m+4=8 are m=2(1+sqrt(2)),m=2(1-sqrt(2))

Find the zeros of m^2-4m+4=8

The zeros of m^2-4m+4=8 are m=2(1+sqrt(2)),m=2(1-sqrt(2))

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m^{2} - 4 m + 4 = 8

m = 2 (1 + 2), m = 2 (1 - 2)

Decimal Notation

m = 4.82842 \dots, m = - 0.82842 \dots

Solution steps

m^{2} - 4 m + 4 = 8

Move

8

to the left side

m^{2} - 4 m - 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 4) = 42

m_{1, 2} = \frac{- ( - 4 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 4 ) + 4 2}{2 \cdot 1}, m_{2} = \frac{- ( - 4 ) - 4 2}{2 \cdot 1}

m = \frac{- ( - 4 ) + 4 2}{2 \cdot 1} : 2 (1 + 2)

m = \frac{- ( - 4 ) - 4 2}{2 \cdot 1} : 2 (1 - 2)

The solutions to the quadratic equation are:

m = 2 (1 + 2), m = 2 (1 - 2)

x^{2} + 5 x - 225 = 0

(1 - 3 (- 1)) x^{2} + 3 x - 4 = 0

x, 6 x^{2} - 9 x + 1 = 0

- 4 x^{2} + x + 3 = 0

81 x^{2} - 5 = 0

What are the solutions to the equation m^2-4m+4=8 ?
The solutions to the equation m^2-4m+4=8 are m=2(1+sqrt(2)),m=2(1-sqrt(2))
Find the zeros of m^2-4m+4=8
The zeros of m^2-4m+4=8 are m=2(1+sqrt(2)),m=2(1-sqrt(2))