What are the solutions to the equation (2x+3)^2=-6 ?

The solutions to the equation (2x+3)^2=-6 are x=-3/2+isqrt(3/2),x=-3/2-isqrt(3/2)

Find the zeros of (2x+3)^2=-6

The zeros of (2x+3)^2=-6 are x=-3/2+isqrt(3/2),x=-3/2-isqrt(3/2)

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(2 x + 3)^{2} = - 6

x = - \frac{3}{2} + i \frac{3}{2}, x = - \frac{3}{2} - i \frac{3}{2}

Solution steps

(2 x + 3)^{2} = - 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 3 = - 6 : x = - \frac{3}{2} + i \frac{3}{2}

Solve

2 x + 3 = - - 6 : x = - \frac{3}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{3}{2}, x = - \frac{3}{2} - i \frac{3}{2}

(3 x + 1) (1 - x) - 3 (x + 1)^{2} = x - 3

6 x^{2} + 10 x - 5 = 0

(x^{2} + 15) = 0

(x - 3)^{2} - 1 = - \frac{3}{4}

12 x^{2} - 20 x + 5 = 0

What are the solutions to the equation (2x+3)^2=-6 ?
The solutions to the equation (2x+3)^2=-6 are x=-3/2+isqrt(3/2),x=-3/2-isqrt(3/2)
Find the zeros of (2x+3)^2=-6
The zeros of (2x+3)^2=-6 are x=-3/2+isqrt(3/2),x=-3/2-isqrt(3/2)