What are the solutions to the equation 49x^2=121 ?

The solutions to the equation 49x^2=121 are x= 11/7 ,x=-11/7

Find the zeros of 49x^2=121

The zeros of 49x^2=121 are x= 11/7 ,x=-11/7

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49 x^{2} = 121

x = \frac{11}{7}, x = - \frac{11}{7}

Decimal Notation

x = 1.57142 \dots, x = - 1.57142 \dots

Solution steps

49 x^{2} = 121

Divide both sides by

49

x^{2} = \frac{121}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{121}{49}, x = - \frac{121}{49}

\frac{121}{49} = \frac{11}{7}

- \frac{121}{49} = - \frac{11}{7}

x = \frac{11}{7}, x = - \frac{11}{7}

x^{2} - 5 x - 3 = 0

x^{2} - 9 x + 20 = 0

s^{2} = - 4

3 x^{2} - 3 x - 20 = 2 x + 8

y^{2} = 0.49

What are the solutions to the equation 49x^2=121 ?
The solutions to the equation 49x^2=121 are x= 11/7 ,x=-11/7
Find the zeros of 49x^2=121
The zeros of 49x^2=121 are x= 11/7 ,x=-11/7