What are the solutions to the equation 24x^2-48x+16=0 ?

The solutions to the equation 24x^2-48x+16=0 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3

Find the zeros of 24x^2-48x+16=0

The zeros of 24x^2-48x+16=0 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3

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24 x^{2} - 48 x + 16 = 0

x = \frac{3 + 3}{3}, x = \frac{3 - 3}{3}

Decimal Notation

x = 1.57735 \dots, x = 0.42264 \dots

Solution steps

24 x^{2} - 48 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 24 \cdot 16}{2 \cdot 24}

(- 48)^{2} - 4 \cdot 24 \cdot 16 = 163

x_{1, 2} = \frac{- ( - 48 ) \pm 16 3}{2 \cdot 24}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 16 3}{2 \cdot 24}, x_{2} = \frac{- ( - 48 ) - 16 3}{2 \cdot 24}

x = \frac{- ( - 48 ) + 16 3}{2 \cdot 24} : \frac{3 + 3}{3}

x = \frac{- ( - 48 ) - 16 3}{2 \cdot 24} : \frac{3 - 3}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 3}{3}, x = \frac{3 - 3}{3}

t^{2} = \frac{2 ( 2 )}{9.8}

121 x^{2} - 462 x + 441 = 360 - 72 x

- 10 x^{2} + 180 = 0

6 x^{2} - 10 x - 19 = 0

x, f (x + h) = 3 x^{2} + 4 x - 2

What are the solutions to the equation 24x^2-48x+16=0 ?
The solutions to the equation 24x^2-48x+16=0 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3
Find the zeros of 24x^2-48x+16=0
The zeros of 24x^2-48x+16=0 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3