What are the solutions to the equation -6x^2+x+12=0 ?

The solutions to the equation -6x^2+x+12=0 are x=-4/3 ,x= 3/2

Find the zeros of -6x^2+x+12=0

The zeros of -6x^2+x+12=0 are x=-4/3 ,x= 3/2

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- 6 x^{2} + x + 12 = 0

x = - \frac{4}{3}, x = \frac{3}{2}

Decimal Notation

x = - 1.33333 \dots, x = 1.5

Solution steps

- 6 x^{2} + x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 6 ) \cdot 12}{2 ( - 6 )}

1^{2} - 4 (- 6) \cdot 12 = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 ( - 6 )}, x_{2} = \frac{- 1 - 17}{2 ( - 6 )}

x = \frac{- 1 + 17}{2 ( - 6 )} : - \frac{4}{3}

x = \frac{- 1 - 17}{2 ( - 6 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = \frac{3}{2}

x + 3 x = 24

3 (3 u - 5) = 39

- \frac{1}{6} \cdot 16

∣ 4 - 8 x ∣ < - 13

3 x^{2} = 8 (2 x - 1)

What are the solutions to the equation -6x^2+x+12=0 ?
The solutions to the equation -6x^2+x+12=0 are x=-4/3 ,x= 3/2
Find the zeros of -6x^2+x+12=0
The zeros of -6x^2+x+12=0 are x=-4/3 ,x= 3/2