What are the solutions to the equation completesquare x^2+5x-9=0 ?

The solutions to the equation completesquare x^2+5x-9=0 are x=(sqrt(61)-5)/2 ,x=(-sqrt(61)-5)/2

Find the zeros of completesquare x^2+5x-9=0

The zeros of completesquare x^2+5x-9=0 are x=(sqrt(61)-5)/2 ,x=(-sqrt(61)-5)/2

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x^{2} + 5 x - 9 = 0

x = \frac{61 - 5}{2}, x = \frac{- 61 - 5}{2}

Decimal Notation

x = 1.40512 \dots, x = - 6.40512 \dots

Solution steps

x^{2} + 5 x - 9 = 0

Move

9

to the right side

x^{2} + 5 x = 9

Rewrite in the form

(x + a)^{2} = b

(x + \frac{5}{2})^{2} = \frac{61}{4}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{5}{2} = \frac{61}{4} : x = \frac{61 - 5}{2}

Solve

x + \frac{5}{2} = - \frac{61}{4} : x = \frac{- 61 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{61 - 5}{2}, x = \frac{- 61 - 5}{2}

x^{2} - 18 x - 7 = 0

15 x - 10 = 6 x (x - 2) + (- x + 3)

2 y^{2} + 5 y = 0

x, f^{- 1} = x^{2} + 7 x + 10

4 x^{2} + 24 x + 45 = 0

What are the solutions to the equation completesquare x^2+5x-9=0 ?
The solutions to the equation completesquare x^2+5x-9=0 are x=(sqrt(61)-5)/2 ,x=(-sqrt(61)-5)/2
Find the zeros of completesquare x^2+5x-9=0
The zeros of completesquare x^2+5x-9=0 are x=(sqrt(61)-5)/2 ,x=(-sqrt(61)-5)/2