What are the solutions to the equation solvefor x,x^2+1=y^3-1 ?

The solutions to the equation solvefor x,x^2+1=y^3-1 are x=sqrt(y^3-2),x=-sqrt(y^3-2)

Find the zeros of solvefor x,x^2+1=y^3-1

The zeros of solvefor x,x^2+1=y^3-1 are x=sqrt(y^3-2),x=-sqrt(y^3-2)

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solve for

x, x^{2} + 1 = y^{3} - 1

x = y^{3} - 2, x = - y^{3} - 2

Solution steps

x^{2} + 1 = y^{3} - 1

Move

1

to the right side

x^{2} = y^{3} - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = y^{3} - 2, x = - y^{3} - 2

2 x^{2} + x - 10 = 0

u^{2} - 3 u = - 54

6 = 7 x - 2 x^{2}

a^{2} = 6 a - 9

- 3 x^{2} - 2 x = - 1

What are the solutions to the equation solvefor x,x^2+1=y^3-1 ?
The solutions to the equation solvefor x,x^2+1=y^3-1 are x=sqrt(y^3-2),x=-sqrt(y^3-2)
Find the zeros of solvefor x,x^2+1=y^3-1
The zeros of solvefor x,x^2+1=y^3-1 are x=sqrt(y^3-2),x=-sqrt(y^3-2)