What are the solutions to the equation (x^2-5x)=6 ?

The solutions to the equation (x^2-5x)=6 are x=6,x=-1

Find the zeros of (x^2-5x)=6

The zeros of (x^2-5x)=6 are x=6,x=-1

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(x^{2} - 5 x) = 6

x = 6, x = - 1

Solution steps

(x^{2} - 5 x) = 6

Refine

x^{2} - 5 x = 6

Move

6

to the left side

x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

x = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

x = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 6, x = - 1

28 = 5 r + 3 r^{2}

x, 9 x^{2} + 36 y^{2} = 0

2 x^{2} + 4 x + 38 = - 6

6 x^{2} + 72 x + 600 = 0

x^{2} + 12 x - 44 = 64

What are the solutions to the equation (x^2-5x)=6 ?
The solutions to the equation (x^2-5x)=6 are x=6,x=-1
Find the zeros of (x^2-5x)=6
The zeros of (x^2-5x)=6 are x=6,x=-1