What are the solutions to the equation 17^2=x^2+5^2 ?

The solutions to the equation 17^2=x^2+5^2 are x=2sqrt(66),x=-2sqrt(66)

Find the zeros of 17^2=x^2+5^2

The zeros of 17^2=x^2+5^2 are x=2sqrt(66),x=-2sqrt(66)

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1 7^{2} = x^{2} + 5^{2}

x = 266, x = - 266

Decimal Notation

x = 16.24807 \dots, x = - 16.24807 \dots

Solution steps

1 7^{2} = x^{2} + 5^{2}

Switch sides

x^{2} + 5^{2} = 1 7^{2}

Move

5^{2}

to the right side

x^{2} = 264

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 264, x = - 264

264 = 266

- 264 = - 266

x = 266, x = - 266

250 = 50 x - 300 - 0.01 x^{2}

5 x^{2} + 70 = 50 x

3 h^{2} - 5 h + 2 = 0

(x - 1)^{2} = - 3

(x - 1)^{2} = 45

What are the solutions to the equation 17^2=x^2+5^2 ?
The solutions to the equation 17^2=x^2+5^2 are x=2sqrt(66),x=-2sqrt(66)
Find the zeros of 17^2=x^2+5^2
The zeros of 17^2=x^2+5^2 are x=2sqrt(66),x=-2sqrt(66)