What are the solutions to the equation x^2+3x-15=-4 ?

The solutions to the equation x^2+3x-15=-4 are x=(-3+sqrt(53))/2 ,x=(-3-sqrt(53))/2

Find the zeros of x^2+3x-15=-4

The zeros of x^2+3x-15=-4 are x=(-3+sqrt(53))/2 ,x=(-3-sqrt(53))/2

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x^{2} + 3 x - 15 = - 4

x = \frac{- 3 + 53}{2}, x = \frac{- 3 - 53}{2}

Decimal Notation

x = 2.14005 \dots, x = - 5.14005 \dots

Solution steps

x^{2} + 3 x - 15 = - 4

Move

4

to the left side

x^{2} + 3 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 11) = 53

x_{1, 2} = \frac{- 3 \pm 53}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 53}{2 \cdot 1}, x_{2} = \frac{- 3 - 53}{2 \cdot 1}

x = \frac{- 3 + 53}{2 \cdot 1} : \frac{- 3 + 53}{2}

x = \frac{- 3 - 53}{2 \cdot 1} : \frac{- 3 - 53}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 53}{2}, x = \frac{- 3 - 53}{2}

2 x (x - 2) = x + 3

x, - x^{2} + 2 x = y

x^{2} - 4 (2 + x) = 13

3 x^{2} - 10 x = 6 x - x^{2} - 15

x, (x + y) (x - y) = (x - y) 2

What are the solutions to the equation x^2+3x-15=-4 ?
The solutions to the equation x^2+3x-15=-4 are x=(-3+sqrt(53))/2 ,x=(-3-sqrt(53))/2
Find the zeros of x^2+3x-15=-4
The zeros of x^2+3x-15=-4 are x=(-3+sqrt(53))/2 ,x=(-3-sqrt(53))/2