What are the solutions to the equation solvefor y,0=3y-2xy-3y^2 ?

The solutions to the equation solvefor y,0=3y-2xy-3y^2 are y=0,y=(3-2x)/3

Find the zeros of solvefor y,0=3y-2xy-3y^2

The zeros of solvefor y,0=3y-2xy-3y^2 are y=0,y=(3-2x)/3

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solve for

y, 0 = 3 y - 2 x y - 3 y^{2}

y = 0, y = \frac{3 - 2 x}{3}

Solution steps

0 = 3 y - 2 x y - 3 y^{2}

Switch sides

3 y - 2 x y - 3 y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 y^{2} + (3 - 2 x) y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( 3 - 2 x ) \pm ( 3 - 2 x ) ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

Simplify

(3 - 2 x)^{2} - 4 (- 3) \cdot 0 : - 2 x + 3

y_{1, 2} = \frac{- ( 3 - 2 x ) \pm ( - 2 x + 3 )}{2 ( - 3 )}

Separate the solutions

y_{1} = \frac{- ( 3 - 2 x ) - 2 x + 3}{2 ( - 3 )}, y_{2} = \frac{- ( 3 - 2 x ) - ( - 2 x + 3 )}{2 ( - 3 )}

y = \frac{- ( 3 - 2 x ) - 2 x + 3}{2 ( - 3 )} : 0

y = \frac{- ( 3 - 2 x ) - ( - 2 x + 3 )}{2 ( - 3 )} : \frac{3 - 2 x}{3}

The solutions to the quadratic equation are:

y = 0, y = \frac{3 - 2 x}{3}

x, a x^{2} + b x = - c

4 x^{2} + 10 x - 15 = 0

x^{2} - 10 \cdot x + 24 = 0

60 t + 1.05 t^{2} = 800

9 x^{2} = 10 x + 2

What are the solutions to the equation solvefor y,0=3y-2xy-3y^2 ?
The solutions to the equation solvefor y,0=3y-2xy-3y^2 are y=0,y=(3-2x)/3
Find the zeros of solvefor y,0=3y-2xy-3y^2
The zeros of solvefor y,0=3y-2xy-3y^2 are y=0,y=(3-2x)/3