What are the solutions to the equation 8+x^2+3x=0 ?

The solutions to the equation 8+x^2+3x=0 are x=-3/2+i(sqrt(23))/2 ,x=-3/2-i(sqrt(23))/2

Find the zeros of 8+x^2+3x=0

The zeros of 8+x^2+3x=0 are x=-3/2+i(sqrt(23))/2 ,x=-3/2-i(sqrt(23))/2

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8 + x^{2} + 3 x = 0

x = - \frac{3}{2} + i \frac{23}{2}, x = - \frac{3}{2} - i \frac{23}{2}

Solution steps

8 + x^{2} + 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 3 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

3^{2} - 4 \cdot 1 \cdot 8 : 23 i

x_{1, 2} = \frac{- 3 \pm 23 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 23 i}{2 \cdot 1}, x_{2} = \frac{- 3 - 23 i}{2 \cdot 1}

x = \frac{- 3 + 23 i}{2 \cdot 1} : - \frac{3}{2} + i \frac{23}{2}

x = \frac{- 3 - 23 i}{2 \cdot 1} : - \frac{3}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{23}{2}, x = - \frac{3}{2} - i \frac{23}{2}

- x^{2} + 6 x - 11 = 0

(x + 2) (x + 9) = 0

6 1^{2} = 5 0^{2} + x^{2}

9 x^{2} - 18 x + 6 = 0

25 x^{2} = 16 x

What are the solutions to the equation 8+x^2+3x=0 ?
The solutions to the equation 8+x^2+3x=0 are x=-3/2+i(sqrt(23))/2 ,x=-3/2-i(sqrt(23))/2
Find the zeros of 8+x^2+3x=0
The zeros of 8+x^2+3x=0 are x=-3/2+i(sqrt(23))/2 ,x=-3/2-i(sqrt(23))/2