What are the solutions to the equation 4b^2-9b=133 ?

The solutions to the equation 4b^2-9b=133 are b=7,b=-19/4

Find the zeros of 4b^2-9b=133

The zeros of 4b^2-9b=133 are b=7,b=-19/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 b^{2} - 9 b = 133

b = 7, b = - \frac{19}{4}

Decimal Notation

b = 7, b = - 4.75

Solution steps

4 b^{2} - 9 b = 133

Move

133

to the left side

4 b^{2} - 9 b - 133 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 ( - 133 )}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 (- 133) = 47

b_{1, 2} = \frac{- ( - 9 ) \pm 47}{2 \cdot 4}

Separate the solutions

b_{1} = \frac{- ( - 9 ) + 47}{2 \cdot 4}, b_{2} = \frac{- ( - 9 ) - 47}{2 \cdot 4}

b = \frac{- ( - 9 ) + 47}{2 \cdot 4} : 7

b = \frac{- ( - 9 ) - 47}{2 \cdot 4} : - \frac{19}{4}

The solutions to the quadratic equation are:

b = 7, b = - \frac{19}{4}

0.1 n^{2} + 100 n = 992

(2 x - 7) (x + 3) = 4

- 5 (x)^{2} - 5 x + 200 = 0

- 2 x^{2} + 8 = 6 x

3 x^{2} = 2 (3 x - 1)

What are the solutions to the equation 4b^2-9b=133 ?
The solutions to the equation 4b^2-9b=133 are b=7,b=-19/4
Find the zeros of 4b^2-9b=133
The zeros of 4b^2-9b=133 are b=7,b=-19/4