What are the solutions to the equation n(n-3)=70 ?

The solutions to the equation n(n-3)=70 are n=10,n=-7

Find the zeros of n(n-3)=70

The zeros of n(n-3)=70 are n=10,n=-7

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n (n - 3) = 70

n = 10, n = - 7

Solution steps

n (n - 3) = 70

Expand

n (n - 3) : n^{2} - 3 n

n^{2} - 3 n = 70

Move

70

to the left side

n^{2} - 3 n - 70 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 70 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 70) = 17

n_{1, 2} = \frac{- ( - 3 ) \pm 17}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 3 ) + 17}{2 \cdot 1}, n_{2} = \frac{- ( - 3 ) - 17}{2 \cdot 1}

n = \frac{- ( - 3 ) + 17}{2 \cdot 1} : 10

n = \frac{- ( - 3 ) - 17}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

n = 10, n = - 7

5 x^{2} = 81

5 x^{2} = 12

- 15 x^{2} - 7 x + 2 = 0

3 (x - 3) (x + 4) = 0

x, y = x^{2} - 7

What are the solutions to the equation n(n-3)=70 ?
The solutions to the equation n(n-3)=70 are n=10,n=-7
Find the zeros of n(n-3)=70
The zeros of n(n-3)=70 are n=10,n=-7