What are the solutions to the equation x(x-2)=(3x+5)(x-2) ?

The solutions to the equation x(x-2)=(3x+5)(x-2) are x=2,x=-5/2

Find the zeros of x(x-2)=(3x+5)(x-2)

The zeros of x(x-2)=(3x+5)(x-2) are x=2,x=-5/2

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x (x - 2) = (3 x + 5) (x - 2)

x = 2, x = - \frac{5}{2}

Decimal Notation

x = 2, x = - 2.5

Solution steps

x (x - 2) = (3 x + 5) (x - 2)

Move

(3 x + 5) (x - 2)

to the left side

x (x - 2) - (3 x + 5) (x - 2) = 0

Factor

x (x - 2) - (3 x + 5) (x - 2) : - (x - 2) (2 x + 5)

- (x - 2) (2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x + 5 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{5}{2}

2 y^{2} - y + 3 = 0

- 2 x^{2} + 18 x - 40 = 0

2 y^{2} - y + 4 = 0

2 x (x - 1) = x^{2} - 1

4 t^{2} - t - 7 = 2 t^{2}

What are the solutions to the equation x(x-2)=(3x+5)(x-2) ?
The solutions to the equation x(x-2)=(3x+5)(x-2) are x=2,x=-5/2
Find the zeros of x(x-2)=(3x+5)(x-2)
The zeros of x(x-2)=(3x+5)(x-2) are x=2,x=-5/2