What are the solutions to the equation 9x^2-3x=20 ?

The solutions to the equation 9x^2-3x=20 are x= 5/3 ,x=-4/3

Find the zeros of 9x^2-3x=20

The zeros of 9x^2-3x=20 are x= 5/3 ,x=-4/3

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9 x^{2} - 3 x = 20

x = \frac{5}{3}, x = - \frac{4}{3}

Decimal Notation

x = 1.66666 \dots, x = - 1.33333 \dots

Solution steps

9 x^{2} - 3 x = 20

Move

20

to the left side

9 x^{2} - 3 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 9 ( - 20 )}{2 \cdot 9}

(- 3)^{2} - 4 \cdot 9 (- 20) = 27

x_{1, 2} = \frac{- ( - 3 ) \pm 27}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 27}{2 \cdot 9}, x_{2} = \frac{- ( - 3 ) - 27}{2 \cdot 9}

x = \frac{- ( - 3 ) + 27}{2 \cdot 9} : \frac{5}{3}

x = \frac{- ( - 3 ) - 27}{2 \cdot 9} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - \frac{4}{3}

- x^{2} + x - 1 = 0

x^{2} + 8 x - 23 = 0

x^{2} - 4 x + 8 = 0

4 y^{2} + 8 y + 5 = 0

(12 - 1.9 t)^{2} = 0

What are the solutions to the equation 9x^2-3x=20 ?
The solutions to the equation 9x^2-3x=20 are x= 5/3 ,x=-4/3
Find the zeros of 9x^2-3x=20
The zeros of 9x^2-3x=20 are x= 5/3 ,x=-4/3