What are the solutions to the equation 35x^2-8x-3=0 ?

The solutions to the equation 35x^2-8x-3=0 are x= 3/7 ,x=-1/5

Find the zeros of 35x^2-8x-3=0

The zeros of 35x^2-8x-3=0 are x= 3/7 ,x=-1/5

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35 x^{2} - 8 x - 3 = 0

x = \frac{3}{7}, x = - \frac{1}{5}

Decimal Notation

x = 0.42857 \dots, x = - 0.2

Solution steps

35 x^{2} - 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 35 ( - 3 )}{2 \cdot 35}

(- 8)^{2} - 4 \cdot 35 (- 3) = 22

x_{1, 2} = \frac{- ( - 8 ) \pm 22}{2 \cdot 35}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 22}{2 \cdot 35}, x_{2} = \frac{- ( - 8 ) - 22}{2 \cdot 35}

x = \frac{- ( - 8 ) + 22}{2 \cdot 35} : \frac{3}{7}

x = \frac{- ( - 8 ) - 22}{2 \cdot 35} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{3}{7}, x = - \frac{1}{5}

(x - 3)^{2} - (2 x + 5^{2}) = - 26 x - 28

4 x^{2} + 8 n = 36

13 + 12 x - x^{2}

6 x^{2} = x + 1

(x + 2)^{2} + (x - 1)^{2} = 9

What are the solutions to the equation 35x^2-8x-3=0 ?
The solutions to the equation 35x^2-8x-3=0 are x= 3/7 ,x=-1/5
Find the zeros of 35x^2-8x-3=0
The zeros of 35x^2-8x-3=0 are x= 3/7 ,x=-1/5