What are the solutions to the equation c^2=(x+2)^2+(x+2)^2 ?

The solutions to the equation c^2=(x+2)^2+(x+2)^2 are x= c/(sqrt(2))-2,x=-c/(sqrt(2))-2

Find the zeros of c^2=(x+2)^2+(x+2)^2

The zeros of c^2=(x+2)^2+(x+2)^2 are x= c/(sqrt(2))-2,x=-c/(sqrt(2))-2

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c^{2} = (x + 2)^{2} + (x + 2)^{2}

x = \frac{c}{2} - 2, x = - \frac{c}{2} - 2

Solution steps

c^{2} = (x + 2)^{2} + (x + 2)^{2}

Switch sides

(x + 2)^{2} + (x + 2)^{2} = c^{2}

Add similar elements:

(x + 2)^{2} + (x + 2)^{2} = 2 (x + 2)^{2}

2 (x + 2)^{2} = c^{2}

Divide both sides by

2

(x + 2)^{2} = \frac{c ^{2}}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = \frac{c ^{2}}{2} : x = \frac{c}{2} - 2

Solve

x + 2 = - \frac{c ^{2}}{2} : x = - \frac{c}{2} - 2

The solutions to the quadratic equation are:

x = \frac{c}{2} - 2, x = - \frac{c}{2} - 2

x^{2} + 4 x + 3 = 4

6 x^{2} = 2

x^{2} + 4 x + 2 = 2

(x - 2) - 2 (3 x - 1) = x^{2}

z (2 z - 3) = 14

What are the solutions to the equation c^2=(x+2)^2+(x+2)^2 ?
The solutions to the equation c^2=(x+2)^2+(x+2)^2 are x= c/(sqrt(2))-2,x=-c/(sqrt(2))-2
Find the zeros of c^2=(x+2)^2+(x+2)^2
The zeros of c^2=(x+2)^2+(x+2)^2 are x= c/(sqrt(2))-2,x=-c/(sqrt(2))-2