What are the solutions to the equation 12y^2+55y+63=0 ?

The solutions to the equation 12y^2+55y+63=0 are y=-9/4 ,y=-7/3

Find the zeros of 12y^2+55y+63=0

The zeros of 12y^2+55y+63=0 are y=-9/4 ,y=-7/3

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12 y^{2} + 55 y + 63 = 0

y = - \frac{9}{4}, y = - \frac{7}{3}

Decimal Notation

y = - 2.25, y = - 2.33333 \dots

Solution steps

12 y^{2} + 55 y + 63 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 55 \pm 5 5 ^{2} - 4 \cdot 12 \cdot 63}{2 \cdot 12}

5 5^{2} - 4 \cdot 12 \cdot 63 = 1

y_{1, 2} = \frac{- 55 \pm 1}{2 \cdot 12}

Separate the solutions

y_{1} = \frac{- 55 + 1}{2 \cdot 12}, y_{2} = \frac{- 55 - 1}{2 \cdot 12}

y = \frac{- 55 + 1}{2 \cdot 12} : - \frac{9}{4}

y = \frac{- 55 - 1}{2 \cdot 12} : - \frac{7}{3}

The solutions to the quadratic equation are:

y = - \frac{9}{4}, y = - \frac{7}{3}

6 a^{2} - 4 a - 22 = 0

3 r^{2} + 4 r = 1

(2 x + 7)^{2} = 49

- x^{2} + 5 - 4 x = 0

x, f (k - 1) = 5 x^{2} + 4 x - 5

What are the solutions to the equation 12y^2+55y+63=0 ?
The solutions to the equation 12y^2+55y+63=0 are y=-9/4 ,y=-7/3
Find the zeros of 12y^2+55y+63=0
The zeros of 12y^2+55y+63=0 are y=-9/4 ,y=-7/3