What are the solutions to the equation -5x^2+9=0 ?

The solutions to the equation -5x^2+9=0 are x= 3/(sqrt(5)),x=-3/(sqrt(5))

Find the zeros of -5x^2+9=0

The zeros of -5x^2+9=0 are x= 3/(sqrt(5)),x=-3/(sqrt(5))

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- 5 x^{2} + 9 = 0

x = \frac{3}{5}, x = - \frac{3}{5}

Decimal Notation

x = 1.34164 \dots, x = - 1.34164 \dots

Solution steps

- 5 x^{2} + 9 = 0

Move

9

to the right side

- 5 x^{2} = - 9

Divide both sides by

- 5

x^{2} = \frac{9}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{5}, x = - \frac{9}{5}

\frac{9}{5} = \frac{3}{5}

- \frac{9}{5} = - \frac{3}{5}

x = \frac{3}{5}, x = - \frac{3}{5}

- 8 x^{2} + 2 x + 10

a^{2} + 3. 4^{2} = 5. 6^{2}

6 t^{2} + 36 = 0

4 s^{2} - 20 s + 25 = 0

3 x^{2} - 8 x - 3 = 0

What are the solutions to the equation -5x^2+9=0 ?
The solutions to the equation -5x^2+9=0 are x= 3/(sqrt(5)),x=-3/(sqrt(5))
Find the zeros of -5x^2+9=0
The zeros of -5x^2+9=0 are x= 3/(sqrt(5)),x=-3/(sqrt(5))