What are the solutions to the equation 5x^2+4x-8=0 ?

The solutions to the equation 5x^2+4x-8=0 are x=(2(sqrt(11)-1))/5 ,x=-(2(1+sqrt(11)))/5

Find the zeros of 5x^2+4x-8=0

The zeros of 5x^2+4x-8=0 are x=(2(sqrt(11)-1))/5 ,x=-(2(1+sqrt(11)))/5

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5 x^{2} + 4 x - 8 = 0

x = \frac{2 ( 11 - 1 )}{5}, x = - \frac{2 ( 1 + 11 )}{5}

Decimal Notation

x = 0.92664 \dots, x = - 1.72664 \dots

Solution steps

5 x^{2} + 4 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 ( - 8 )}{2 \cdot 5}

4^{2} - 4 \cdot 5 (- 8) = 411

x_{1, 2} = \frac{- 4 \pm 4 11}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 4 + 4 11}{2 \cdot 5}, x_{2} = \frac{- 4 - 4 11}{2 \cdot 5}

x = \frac{- 4 + 4 11}{2 \cdot 5} : \frac{2 ( 11 - 1 )}{5}

x = \frac{- 4 - 4 11}{2 \cdot 5} : - \frac{2 ( 1 + 11 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 11 - 1 )}{5}, x = - \frac{2 ( 1 + 11 )}{5}

3 x^{2} - x

3 x^{2} + 35 = 24 x - 1

15 x^{2} - 13 x - 6 = 0

2 c t - 3 b t^{2} = 0

x (x - 8) = 20

What are the solutions to the equation 5x^2+4x-8=0 ?
The solutions to the equation 5x^2+4x-8=0 are x=(2(sqrt(11)-1))/5 ,x=-(2(1+sqrt(11)))/5
Find the zeros of 5x^2+4x-8=0
The zeros of 5x^2+4x-8=0 are x=(2(sqrt(11)-1))/5 ,x=-(2(1+sqrt(11)))/5